On this page
- 01What makes up the heat load of a cold room?
- 02How do you calculate transmission load through walls, roof and floor?
- 03How do you calculate product load, respiration and freezing heat?
- 04How much heat enters through door openings?
- 05What internal loads should you include?
- 06Worked example: 5 × 4 × 3 m produce chiller at 45 °C ambient
- 07How do safety margin and run-time hours change the machine size?
- 08How does HyperCold turn the heat load into a Daikin machine?
- FAQFrequently asked questions
Quick answer
Cold room heat load is the sum of transmission (U × A × ΔT), product pull-down and respiration, door infiltration and internal loads (people, lights, fans), plus a 10–20% margin, divided by compressor run hours. A 5 × 4 × 3 m produce chiller at +4 °C and 45 °C ambient needs about 5.3 kW (1.5 TR).
Key takeaways
- With 100 mm PUF (k = 0.022 W/m·K) the U-value is 0.22 W/m²·K, so each square metre of a +4 °C room gains about 9 W on a 45 °C day.
- In a small chiller that takes fresh stock daily, product pull-down and respiration can be half the load: 51% in the worked example, against 24% for the envelope.
- Divide the daily load by 16–18 compressor run hours for chillers and 18–20 hours for freezers, never by 24.
- Freezing is dominated by latent heat: at about 280 kJ/kg for a high-moisture product it is 83% of the total freezing load in the example below.
- 1 TR = 3.517 kW; HyperCold's configurator then selects a Daikin unit, such as the 8 kW, 4 HP MT unit for a 2,119 cu ft chiller.
What makes up the heat load of a cold room?
The refrigeration load is the heat that must be removed every 24 hours to hold the set-point. It is built from four groups — transmission, product, infiltration and internal loads — each calculated separately and then added.
| Load component | What drives it | Basic formula |
|---|---|---|
| Transmission | Wall, roof and floor area, panel thickness, ambient minus room temperature | Q = U × A × ΔT |
| Product, sensible | Daily intake and how warm it arrives | Q = m × cp × ΔT |
| Product, latent | Freezing the water in the product | Q = m × L |
| Respiration | Live produce giving off heat in storage | Q = stock (t) × W/t |
| Infiltration | Door openings and air leakage | Q = V × air changes × Δh |
| Internal | People, lights, evaporator fans, defrost, forklifts | Q = W × hours |
In a large bulk store the envelope dominates: HyperCold's electricity guide puts envelope conduction at 35–55% and door infiltration at 15–28% of cooling load in a typical cold store. In a small room that receives fresh stock every day, the product load can overtake the envelope, which is why no single thumb rule works for both.
How do you calculate transmission load through walls, roof and floor?
Transmission load is Q = U × A × ΔT: U is the panel's heat transfer coefficient (W/m²·K), A the total area of walls, ceiling and floor (m²) and ΔT the design ambient minus room temperature (in K, numerically equal to the °C difference). For a PUF panel, U ≈ k ÷ thickness. HyperCold's heat load calculator uses k = 0.022 W/m·K, a typical IS 12436 value, and applies the full ambient ΔT to all six faces, which is conservative for a floor on ground.
| PPGL PUF panel | U-value | Rate-card band | ΔT at 45 °C | Heat gain |
|---|---|---|---|---|
| 60 mm | 0.367 W/m²·K | +15 to +25 °C | 30 K | 11.0 W/m² |
| 80 mm | 0.275 W/m²·K | +8 to +15 °C | 37 K | 10.2 W/m² |
| 100 mm | 0.220 W/m²·K | 0 to +8 °C | 45 K | 9.9 W/m² |
| 120 mm | 0.183 W/m²·K | −18 to −25 °C | 70 K | 12.8 W/m² |
| 150 mm | 0.147 W/m²·K | −30 to −40 °C | 85 K | 12.5 W/m² |
ΔT is taken at the cold end of each band. The calculator defaults to 45 °C design ambient, matching the 44–46 °C summer peaks of the composite zone (Delhi, Lucknow); hot-dry Rajasthan sites reach 46–48 °C, and coastal cities peak at 38–42 °C but with far more humidity. Sun on an exposed roof adds load, so rooms belong under a shed. Ageing foam and unsealed joints push real U-values above these figures.
How do you calculate product load, respiration and freezing heat?
Product load has up to three parts:
- Sensible pull-down: Q = m × cp × ΔT. With cp ≈ 3.85 kJ/kg·K (the calculator's default for fresh, high-moisture food), 1,000 kg arriving at 29 °C and cooled to 4 °C needs 1,000 × 3.85 × 25 = 96,250 kJ.
- Respiration: fruit and vegetables keep respiring, so the whole stock generates heat, not only the day's intake. Published values (ASHRAE, USDA Handbook 66) vary by variety and source, from roughly 10–25 W/t for apple near 0 °C to about 100 W/t for mushroom at the same temperature, and rise steeply as temperature goes up. The calculator's defaults are 60 W/t for chilled produce, 120 W/t for banana ripening and 180 W/t for mushroom.
- Latent heat of freezing: Q = m × L, where L ≈ water content × 334 kJ/kg. The calculator uses 280 kJ/kg (about 84% water) and cp ≈ 1.93 kJ/kg·K for the frozen product.
Freezing 500 kg from +5 °C to −20 °C by the calculator method (freezing point taken as 0 °C): 500 × 3.85 × 5 = 9,625 kJ, plus 500 × 280 = 1,40,000 kJ, plus 500 × 1.93 × 20 = 19,300 kJ, a total of 1,68,925 kJ. Latent heat is 83% of it. Spread over 24 hours that is 1.96 kW; done in an 8-hour batch it is 5.87 kW for the product alone — the reason fresh product is frozen in a blast freezer, not a storage freezer (see blast freezer vs cold room).
To convert any product load to power: kW = kJ ÷ (hours allowed × 3,600).
How much heat enters through door openings?
Infiltration load is Q = V × N × Δh, where V is room volume (m³), N the air changes per day and Δh the heat removed from each cubic metre of incoming air (kJ/m³). The calculator uses Δh = 60 kJ/m³ for chilled rooms and 100 kJ/m³ for sub-zero rooms. Humid monsoon air carries more heat than dry summer air, one reason for the safety margin.
N depends on room size and door discipline. Reference tables based on ASHRAE data give roughly 12 air changes a day for a 60 m³ room in average use, about 5 for a 300 m³ room, and about double under heavy use. The calculator's default of 2 a day suits a large, rarely opened store, not a busy walk-in. A self-closing door, strip curtain or ante room cuts N sharply; compare the options in the cold room doors guide.
What internal loads should you include?
| Internal source | Value to use | Note |
|---|---|---|
| Person working inside | 270 W each | Calculator default; ASHRAE gives about 270 W at 0 °C and 390 W at −20 °C |
| Lighting | 10 W/m² of ceiling | Calculator default; LED fittings can be lower |
| Evaporator fan motors | Rated W × running hours | From the unit-cooler datasheet; fans often run 24 h |
| Electric defrost | Heater kW × defrost time, partly | Not needed for off-cycle defrost above about +2 °C |
| Forklift or pallet truck | Motor kW × time inside | Calculator assumes 15% of the day |
The calculator applies people and lighting for 25% of the day (6 hours). It has no separate line for evaporator fans or defrost heat; at first-cut stage these sit inside the 10% margin, and the engineering sheet adds them from the actual evaporator datasheet.
Worked example: 5 × 4 × 3 m produce chiller at 45 °C ambient
Assumptions, stated so every figure can be checked:
- Internal size 5 × 4 × 3 m: volume 60 m³ (2,119 cu ft); area = walls 54 + ceiling 20 + floor 20 = 94 m²
- 100 mm PPGL PUF on all six faces (the rate-card thickness for 0 to +8 °C), U = 0.22 W/m²·K
- Room +4 °C, design ambient 45 °C, so ΔT = 41 K
- Stock 12 t of fresh produce; intake 1,000 kg/day arriving at 29 °C
- 12 air changes/day at 60 kJ/m³; one person and 10 W/m² lighting for 6 h/day
- Evaporator fans assumed at 0.3 kW running 24 h (use the datasheet figure in practice)
| Component | Working | kJ/day |
|---|---|---|
| Transmission | 0.22 × 94 × 41 × 86.4 | 73,257 |
| Product pull-down | 1,000 × 3.85 × 25 | 96,250 |
| Respiration | 12 t × 60 W/t × 86.4 | 62,208 |
| Infiltration | 60 × 12 × 60 | 43,200 |
| People | 270 W × 6 h × 3.6 | 5,832 |
| Lighting | 200 W × 6 h × 3.6 | 4,320 |
| Evaporator fans | 300 W × 24 h × 3.6 | 25,920 |
| Subtotal | sum of the above | 3,10,987 |
| Safety margin | 10% of subtotal | 31,099 |
| Design load | subtotal + margin | 3,42,086 |
Multiplying watts by 86.4 gives kJ per day; multiplying watt-hours by 3.6 gives kJ. The envelope gains 848 W, only 24% of the subtotal, while product pull-down and respiration together are 51%. As a 24-hour average the design load is 3,42,086 ÷ 86,400 = 3.96 kW (1.13 TR) — but that is not yet the machine size.
How do safety margin and run-time hours change the machine size?
Two corrections turn the daily load into a capacity:
- Safety margin. HyperCold's calculator adds 10% as a first cut. HyperCold's design checklist uses 15–20% for north India and 25% for Rajasthan and coastal Gujarat when finalising, because door discipline, intake temperature and ambient peaks are uncertain.
- Run time. Compressors are not sized to run 24 hours: time goes to defrost, and the system needs reserve to recover after door openings. Common practice is 16–18 run hours a day for chillers and 18–20 hours for freezers with automatic defrost.
| Case | Daily load | Run time | Required capacity |
|---|---|---|---|
| 24-hour average, 10% margin | 3,42,086 kJ | 24 h | 3.96 kW (1.13 TR) |
| 10% margin, 18 h run | 3,42,086 kJ | 18 h | 5.28 kW (1.50 TR) |
| 20% margin, 16 h run | 3,73,184 kJ | 16 h | 6.48 kW (1.84 TR) |
Conversions: kW = kJ per day ÷ (run hours × 3,600); TR = kW ÷ 3.517. Size to the run-time figure, never to the 24-hour average.
How does HyperCold turn the heat load into a Daikin machine?
HyperCold's quotation configurator selects Daikin condensing units by room type and internal volume from its machine-selection charts, and the heat load calculator shows that match next to the physics result. For this 60 m³ (2,119 cu ft) chiller it selects one CCMS0400ARY16 (4 HP, MT series, 8 kW) with a CRE2M800ASV16 unit cooler, listed at ₹1,22,850 and ₹69,825 on the HyperCold FY2026-27 rate card, GST extra. The requirement of 5.3–6.5 kW is close to or above the 6 kW rating of the 3 HP MT unit, and condensing-unit capacity falls as ambient climbs towards 45 °C, so the 8 kW unit is the right call.
The online calculator is built for a quick 24-hour-average first cut: it applies respiration to the mass entered as daily intake and leaves fan heat inside the margin, so a full engineering sheet like the one above usually comes out higher. Use it to frame the budget, then have the engineering sheet separate stock from intake, add fan and defrost heat and check the unit's capacity table at your site ambient. Final selection and pricing depend on the site survey.
FAQ
Frequently asked questions
How many kW is 1 TR of refrigeration?
One tonne of refrigeration (TR) equals 3.517 kW, or 12,000 BTU/h. Divide kW by 3.517 to get TR; for example, 5.28 kW is 1.50 TR.
Is there a thumb rule for cold room TR per cubic foot?
Volume-based thumb rules ignore daily intake, respiration and door traffic, which can be half the load in a small room. HyperCold's configurator maps volume to a Daikin unit only as a starting point; the heat load calculation confirms or corrects it.
Should the floor be included in the heat load?
Yes. The floor is part of the envelope, and HyperCold's calculator applies the full ambient ΔT to it, which is conservative. HyperCold's cost guide notes that an uninsulated floor can account for 15–22% of cooling load in north Indian summers.
What design ambient temperature should be used in India?
HyperCold's calculator defaults to 45 °C, matching composite-zone peaks of 44–46 °C around Delhi and Lucknow. Hot-dry Rajasthan sites reach 46–48 °C, while coastal Chennai and Mumbai peak at 38–42 °C with higher humidity.
Why does a freezer need a much bigger machine than a chiller of the same size?
ΔT rises from 41 K for a +4 °C room to 65 K for a −20 °C room at 45 °C ambient, and compressor capacity falls at low evaporating temperatures. On HyperCold's rate card a 2 HP unit gives 4 kW in the MT series but only 2 kW in the LT series.
Written by
HyperCold Engineering Team
Cold room and cold storage engineers at HyperCold™, a Daikin equipment partner founded in 2020 and headquartered in Sirsaganj, Firozabad (UP). We design, manufacture PUF panels for, install and maintain cold rooms across India.

